b^2-3b+5=5

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Solution for b^2-3b+5=5 equation:


Simplifying
b2 + -3b + 5 = 5

Reorder the terms:
5 + -3b + b2 = 5

Add '-5' to each side of the equation.
5 + -3b + -5 + b2 = 5 + -5

Reorder the terms:
5 + -5 + -3b + b2 = 5 + -5

Combine like terms: 5 + -5 = 0
0 + -3b + b2 = 5 + -5
-3b + b2 = 5 + -5

Combine like terms: 5 + -5 = 0
-3b + b2 = 0

Solving
-3b + b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), 'b'.
b(-3 + b) = 0

Subproblem 1

Set the factor 'b' equal to zero and attempt to solve: Simplifying b = 0 Solving b = 0 Move all terms containing b to the left, all other terms to the right. Simplifying b = 0

Subproblem 2

Set the factor '(-3 + b)' equal to zero and attempt to solve: Simplifying -3 + b = 0 Solving -3 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + b = 0 + 3 Combine like terms: -3 + 3 = 0 0 + b = 0 + 3 b = 0 + 3 Combine like terms: 0 + 3 = 3 b = 3 Simplifying b = 3

Solution

b = {0, 3}

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